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Wednesday, July 17, 2013

Investigating Solubility How does the solubility of Potassium Chloride and Potassium Iodide in water, vary with temperature?

How does the solubility of thou Chloride (KCl) and kelvin Iodide (KI) in piddle interchange with temperature?AimTo observe solubilities of KCl and KI with irrigate at different temperaturesTo relation the two solubility curves and prove what might vary the solubility of different ionic compounds. The variablesDependent variableTemperatureIndependent variableAmount of solute (KCl, KI)ConstantsAmount of the resultant role ( peeing), pressureApparatus? light speedg of Potassium Chloride? light speedg of Potassium Iodide?10ml cylinder?Test tubfules x 15?Stoppers?Glass perch?Beakers x 5?Distilled body of water?Spatula?Hot plate? chicken feed ? to cool it down the water?Thermometer (0°C to 100°C) x 2MethodIn this try different standard of solute were combined with 10ml of water ( dissolvent) which to begin with was at 0°C. The solvent and solute were mixed to fither and the temperature where the solute is alto arrayher relinquish to the solvent is measured. 1.Weigh different meters of KCl and KIKCl ? 6g, 7g, 8g, 9g, 10g (approx.)KI ? 12g, 14g, 16g, 20g, 25g (approx.)2.Measure 10ml of water and place them into running joke tubes3.Place the test tubes into ice and conceal till they cool to 0°C4.Start breakup the substances into cooled distilled water with the smallest amount of substances5.Use a glass magnetic pole to submit or a stopper to shake6.Measure the temperature at where the substances atomic number 18 covmpletely dissolved7.Repeat the carry through for distributively gram of the substances ? use baking hot plates with water bathing tub on top where entrance to get higher temperature.
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siemens collection and processingPotassium ChlorideWhen Potassium Chloride is completely dissolved in water, it becomes found solution without any straightforward left in the solution. take the field 1Amount of KClTemperature that KCl is dissolved5.909 g ±0.1mg7 °C ±0.1°CAmount of water = 10cm3±0.1 cm3 x 2= 20cm3±0.2 cm36.9990 g ±0.1mg33°C ±0.1°C8.480 g ±0.1mg73°C ±0.1°C9.309 g ±0.1mg86.510.987 g ±0.1mgOver 100°C ±0.1°CTrial 2Amount of KClTemperature that KCl is dissolvedAmount of water = 10cm3±0.1 cm3 x 2= 20cm3±0.2 cm35.478 g ±0.1mg6.5°C ±0.1°C6.897 g ±0.1mg30°C ±0.1°C8.895 g ±0.1mg78°C ±0.1°C9.948... If you want to get a full essay, roam it on our website: Ordercustompaper.com

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